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1 | #include <stdlib.h> | |
2 | #include <errno.h> | |
3 | #include <string.h> | |
4 | ||
5 | #include "store.h" | |
6 | #include "blocktree.h" | |
7 | ||
8 | #define min(a, b) (((b) < (a))?(b):(a)) | |
9 | #define ISDELOP(op) (((op).buf == NULL) && ((op).fillfn == NULL)) | |
10 | ||
11 | ssize_t btget(struct store *st, struct btnode *tree, block_t bl, void *buf, size_t len, size_t blsize) | |
12 | { | |
13 | int d; | |
14 | block_t c, sel; | |
15 | struct btnode indir[1 << blsize]; | |
16 | ssize_t sz; | |
17 | ||
18 | if(tree->d == 0) { | |
19 | errno = ERANGE; | |
20 | return(-1); | |
21 | } | |
22 | while(1) { | |
23 | d = tree->d & 0x7f; | |
24 | /* This check should really only be necessary on the first | |
25 | * iteration, but I felt it was easier to put it in the | |
26 | * loop. */ | |
27 | if((bl >> (d * blsize)) > 0) { | |
28 | errno = ERANGE; | |
29 | return(-1); | |
30 | } | |
31 | ||
32 | if(d == 0) | |
33 | return(storeget(st, buf, len, &tree->a)); | |
34 | ||
35 | /* Luckily, this is tail recursive */ | |
36 | if((sz = storeget(st, indir, sizeof(indir), &tree->a)) < 0) | |
37 | return(-1); | |
38 | c = sz / sizeof(struct btnode); | |
39 | sel = bl >> ((d - 1) * blsize); | |
40 | if(sel >= c) { | |
41 | errno = ERANGE; | |
42 | return(-1); | |
43 | } | |
44 | tree = &indir[sel]; | |
45 | bl &= (1LL << ((d - 1) * blsize)) - 1; | |
46 | } | |
47 | return(0); | |
48 | } | |
49 | ||
50 | static int btputleaf(struct store *st, struct btnode *leaf, struct btop *op, block_t bloff) | |
51 | { | |
52 | void *buf; | |
53 | struct addr na; | |
54 | int ret; | |
55 | ||
56 | if(ISDELOP(*op)) { | |
57 | leaf->d = 0; | |
58 | return(0); | |
59 | } | |
60 | buf = NULL; | |
61 | if(op->buf == NULL) { | |
62 | buf = op->buf = malloc(op->len); | |
63 | if(op->fillfn(buf, op->len, op->pdata)) | |
64 | return(-1); | |
65 | } | |
66 | ret = storeput(st, op->buf, op->len, &na); | |
67 | if(buf != NULL) | |
68 | free(buf); | |
69 | if(ret) | |
70 | return(-1); | |
71 | leaf->d = 0x80; | |
72 | leaf->a = na; | |
73 | return(0); | |
74 | } | |
75 | ||
76 | static int countops(struct btop *ops, int numops, block_t bloff, block_t maxbl) | |
77 | { | |
78 | int i; | |
79 | ||
80 | for(i = 0; i < numops; i++) { | |
81 | if(ops[i].blk - bloff >= maxbl) | |
82 | break; | |
83 | } | |
84 | return(i); | |
85 | } | |
86 | ||
87 | /* | |
88 | * blputmany() in many ways makes the code uglier, but it saves a | |
89 | * *lot* of space, since it doesn't need to store intermediary blocks. | |
90 | */ | |
91 | static int btputmany2(struct store *st, struct btnode *tree, struct btop *ops, int numops, size_t blsize, block_t bloff) | |
92 | { | |
93 | int i, subops, d, f, hasid; | |
94 | block_t c, sel, bl, nextsz; | |
95 | struct addr na; | |
96 | struct btnode indir[1 << blsize]; | |
97 | ssize_t sz; | |
98 | ||
99 | d = tree->d & 0x7f; | |
100 | f = tree->d & 0x80; | |
101 | ||
102 | hasid = 0; | |
103 | ||
104 | for(i = 0; i < numops; ) { | |
105 | if(ops[i].blk < bloff) { | |
106 | errno = ERANGE; | |
107 | return(-1); | |
108 | } | |
109 | bl = ops[i].blk - bloff; | |
110 | ||
111 | if((d == 0) && (bl == 0)) { | |
112 | if(btputleaf(st, tree, ops, bloff)) | |
113 | return(-1); | |
114 | i++; | |
115 | continue; | |
116 | } | |
117 | ||
118 | if(f && (bl == (1LL << (d * blsize)))) { | |
119 | /* New level of indirection */ | |
120 | if(hasid) { | |
121 | if(storeput(st, indir, c * sizeof(struct btnode), &na)) | |
122 | return(-1); | |
123 | tree->a = na; | |
124 | } | |
125 | indir[0] = *tree; | |
126 | tree->d = ++d; | |
127 | f = 0; | |
128 | c = 1; | |
129 | hasid = 1; | |
130 | } else if(d == 0) { | |
131 | /* New tree */ | |
132 | if(bl != 0) { | |
133 | errno = ERANGE; | |
134 | return(-1); | |
135 | } | |
136 | /* Assume that numops == largest block number + 1 -- gaps | |
137 | * will be detected as errors later */ | |
138 | for(bl = numops - 1; bl > 0; d++, bl <<= blsize); | |
139 | tree->d = d; | |
140 | c = 0; | |
141 | hasid = 1; | |
142 | } else { | |
143 | /* Get indirect block */ | |
144 | if(!hasid) { | |
145 | if((sz = storeget(st, indir, sizeof(indir), &tree->a)) < 0) | |
146 | return(-1); | |
147 | c = sz / sizeof(struct btnode); | |
148 | hasid = 1; | |
149 | } | |
150 | } | |
151 | ||
152 | sel = bl >> ((d - 1) * blsize); | |
153 | if(sel > c) { | |
154 | errno = ERANGE; | |
155 | return(-1); | |
156 | } | |
157 | ||
158 | if(sel == c) { | |
159 | /* Append new */ | |
160 | if((c > 0) && (!(indir[c - 1].d & 0x80) || ((indir[c - 1].d & 0x7f) < (d - 1)))) { | |
161 | errno = ERANGE; | |
162 | return(-1); | |
163 | } | |
164 | indir[c].d = 0; | |
165 | c++; | |
166 | } | |
167 | nextsz = 1LL << ((d - 1) * blsize); | |
168 | subops = countops(ops + i, numops - i, bloff + (sel * nextsz), nextsz); | |
169 | if(btputmany2(st, &indir[sel], ops + i, subops, blsize, bloff + (sel * nextsz))) | |
170 | return(-1); | |
171 | i += subops; | |
172 | ||
173 | if((sel == (1 << blsize) - 1) && (indir[sel].d == ((d - 1) | 0x80))) { | |
174 | /* Filled up */ | |
175 | tree->d |= 0x80; | |
176 | f = 1; | |
177 | } else if(indir[sel].d == 0) { | |
178 | /* Erased */ | |
179 | if(--c == 1) { | |
180 | tree->d = indir[0].d; | |
181 | tree->a = indir[0].a; | |
182 | } | |
183 | } | |
184 | } | |
185 | if(hasid) { | |
186 | if(storeput(st, indir, c * sizeof(struct btnode), &na)) | |
187 | return(-1); | |
188 | tree->a = na; | |
189 | } | |
190 | return(0); | |
191 | } | |
192 | ||
193 | int btputmany(struct store *st, struct btnode *tree, struct btop *ops, int numops, size_t blsize) | |
194 | { | |
195 | return(btputmany2(st, tree, ops, numops, blsize, 0)); | |
196 | } | |
197 | ||
198 | int btput(struct store *st, struct btnode *tree, block_t bl, void *buf, size_t len, size_t blsize) | |
199 | { | |
200 | struct btop ops; | |
201 | ||
202 | memset(&ops, 0, sizeof(ops)); | |
203 | ops.blk = bl; | |
204 | ops.buf = buf; | |
205 | ops.len = len; | |
206 | return(btputmany(st, tree, &ops, 1, blsize)); | |
207 | } | |
208 | ||
209 | void btmkop(struct btop *op, block_t bl, void *buf, size_t len) | |
210 | { | |
211 | memset(op, 0, sizeof(*op)); | |
212 | op->blk = bl; | |
213 | op->buf = buf; | |
214 | op->len = len; | |
215 | } | |
216 | ||
217 | static int opcmp(const struct btop **op1, const struct btop **op2) | |
218 | { | |
219 | if(ISDELOP(**op1) && ISDELOP(**op2)) | |
220 | return((*op2)->blk - (*op1)->blk); | |
221 | else if(!ISDELOP(**op1) && ISDELOP(**op2)) | |
222 | return(-1); | |
223 | else if(ISDELOP(**op1) && !ISDELOP(**op2)) | |
224 | return(1); | |
225 | else | |
226 | return((*op1)->blk - (*op2)->blk); | |
227 | } | |
228 | ||
229 | void btsortops(struct btop *ops, int numops) | |
230 | { | |
231 | qsort(ops, numops, sizeof(*ops), (int (*)(const void *, const void *))opcmp); | |
232 | } | |
233 | ||
234 | block_t btcount(struct store *st, struct btnode *tree, size_t blsize) | |
235 | { | |
236 | int d, f; | |
237 | struct btnode indir[1 << blsize]; | |
238 | block_t c, ret; | |
239 | ssize_t sz; | |
240 | ||
241 | d = tree->d & 0x7f; | |
242 | f = tree->d & 0x80; | |
243 | ||
244 | if(f) | |
245 | return(1LL << (d * blsize)); | |
246 | ||
247 | if(d == 0) | |
248 | return(0); | |
249 | ||
250 | ret = 0; | |
251 | while(1) { | |
252 | if((sz = storeget(st, indir, sizeof(indir), &tree->a)) < 0) | |
253 | return(-1); | |
254 | c = sz / sizeof(struct btnode); | |
255 | ret += (c - 1) * (1LL << ((d - 1) * blsize)); | |
256 | d = indir[c - 1].d & 0x7f; | |
257 | f = indir[c - 1].d & 0x80; | |
258 | if(f) | |
259 | return(ret + (1LL << (d * blsize))); | |
260 | tree = &indir[c - 1]; | |
261 | } | |
262 | } |